35x^2-40=0

Solution for 35x^2-40=0 equation:

35x^2-40=0

a = 35; b = 0; c = -40;
Δ = b2-4ac
Δ = 02-4·35·(-40)
Δ = 5600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{5600}=\sqrt{400*14}=\sqrt{400}*\sqrt{14}=20\sqrt{14}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-20\sqrt{14}}{2*35}=\frac{0-20\sqrt{14}}{70}
=-\frac{20\sqrt{14}}{70}
=-\frac{2\sqrt{14}}{7}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+20\sqrt{14}}{2*35}=\frac{0+20\sqrt{14}}{70}
=\frac{20\sqrt{14}}{70}
=\frac{2\sqrt{14}}{7}
$